A few years ago GLR support was added to Bison, enabling it to process ambiguous grammars, and I decided to create a C parser that simply skipped all preprocessing directives. I knew that at least one reasonably common usage would generate a syntax error:

func_call(a,
#if SOME_FLAG
b_1);
#else
b_2);
#endif

c);
and wanted to minimize its consequences (i.e., cascading syntax errors to the end of the file). The solution chosen was to parse the source a single statement or declaration at a time, so any syntax error would be localized to a single statement or declaration.

Systems for parsing ambiguous grammars work on the basis that while the input may be locally ambiguous, once enough tokens have been seen the number of possible parses will be reduced to one. In C (and even more so in C++) there are some situations where it is impossible to resolve which of several possible parses apply without declaration information on one or more of the identifiers involved (a traditional parser would maintain a symbol table where this information could be obtained when needed). For instance, x * y; could be a declaration of the identifier y to have type x or an expression statement that multiplies x and y. My parser did not have a symbol table and even if it did the lack of header file processing meant that its contents would only contain a partial set of the declared identifiers. The ambiguity resolution strategy I adopted was to pick the most likely case, which in the example is the declaration parse.

Other constructs where the common case (chosen by me and I have yet to get around to actually verifying via measurement) was used to resolve an ambiguity deadlock included:

f(p);      // Very common, 
            // confidently picked function call as the common case
(m)*p;   // Not rare,
            // confidently picked multiplication as the common case
(s) - t;      // Quiet rare,
               // picked binary operator as the common case
(r) + (s) - t; // Very rare,
                  //an iteration on the case above

At the moment I am using the parser to measure language usage, so less than 100% correctness can be tolerated. Some of the constructs that cause a syntax error to be generated every few hundred statement/declarations include:

offsetof(struct tag, field_name)  // Declarators cannot be 
                                            //function arguments
int f(p, q)
int p;     // Tries to reduce this as a declaration without handling
char q;   // it as part of an old style function definition
{
 
MACRO(+); // Preprocessing expands to something meaningful

Some of these can be handled by extensions to the grammar, while others could be handled by an error recovery mechanism that recognized likely macro usage and inserted something appropriate (e.g., a dummy expression in the MACRO(x) case).

For example, a struct containing five fields has four field pairs having distance 1 from each other, three distance 2, two distance 2, and one field pair having distance 4; the average is 2.

The surprising answer, to me at least, is (N+1)/3.

Proof: The average distance can be obtained by summing the distances between all possible field pairs and dividing this value by the number of possible different pairs.

                  Distance 1  2  3  4  5  6
Number of fields
            4              3  2  1
            5              4  3  2  1
            6              5  4  3  2  1
            7              6  5  4  3  2  1

The above table shows the pattern that occurs as the number of fields in a definition increases.

In the case of a definition containing five fields the sum of the distances of all field pairs is: (4*1 + 3*2 + 2*3 + 1*4) and the number of different pairs is: (4+3+2+1). Dividing these two values gives the average distance between two randomly chosen fields, e.g., 2.

Summing the distance over every field pair for a definition containing 3, 4, 5, 6, 7, 8, … fields gives the sequence: 1, 4, 10, 20, 35, 56, … This is sequence A000292 in the On-Line Encyclopedia of Integer sequences and is given by the formula n*(n+1)*(n+2)/6 (where n = N − 1, i.e., the number of fields minus 1).

Summing the number of different field pairs for definitions containing increasing numbers of fields gives the sequence: 1, 3, 6, 10, 15, 21, 28, … This is sequence A000217 and is given by the formula n*(n + 1)/2.

Dividing these two formula and simplifying yields (N + 1)/3.